Find online A-level maths tutors

Latimer offers online one-to-one tuition. Microsoft Teams is the default lesson platform; you and the tutor can agree another. Before the first lesson, decide how you will both see the learner’s working. A clear view of each line matters when a missing bracket, negative sign or unexplained jump changes the answer.

Here is an illustrative A-level question: differentiate y = (3x − 2)⁴. A learner writes dy/dx = 4(3x − 2)³. They have differentiated the fourth power but missed the changing expression inside the bracket.

Let u = 3x − 2. Then y = u⁴, so dy/du = 4u³, while du/dx = 3. The chain rule multiplies these rates: dy/dx = 4(3x − 2)³ × 3 = 12(3x − 2)³. Keeping the inner derivative on its own line makes the missing factor visible.

The next step is to use the derivative. At x = 1, the point on the curve is (1, 1) and the gradient is 12. The tangent therefore has equation y − 1 = 12(x − 1), or y = 12x − 11. This connects a differentiation rule to coordinate geometry.

Online, the learner can mark the inner expression and explain why its derivative is needed before the tutor adds a correction. For independent follow-up, differentiate (2x + 1)⁵: the answer is 10(2x + 1)⁴. Explaining where the factor 2 comes from is a more useful check than copying the first solution.

Suppose an illustrative model has 10 independent trials, each with the same success probability 0.2. Let X count the successes, so X follows a binomial distribution with n = 10 and p = 0.2. What is the probability of at least three successes?

“At least three” includes 3, 4, …, 10. Its opposite is 0, 1 or 2, so P(X ≥ 3) = 1 − P(X ≤ 2). A cumulative binomial calculation gives P(X ≤ 2) ≈ 0.6777995, and the required probability is approximately 0.3222, or 32.2%.

An incorrect approach is to calculate 1 − P(X ≤ 3). That also removes the case X = 3 and answers a different question: more than three successes. Write the event in symbols before entering the calculator values. Then explain the answer in words: under this model, there is about a 32.2% chance of three or more successes.

In an online lesson, a tutor and learner can compare the written inequality with the calculator input. The discussion should also test the model: if trials affect one another, or the success probability changes, these binomial assumptions need reconsidering.

Consider a particle moving along a straight line with velocity v = 2t − 4 metres per second, from t = 0 to t = 5 seconds. Integrating velocity gives the change in position, or displacement. It does not automatically give the total distance travelled.

The velocity is zero when 2t − 4 = 0, so the particle turns at t = 2 seconds. Before that, velocity is negative; afterwards it is positive. The velocity–time graph is a straight line from (0, −4) through (2, 0) to (5, 6).

From 0 to 2 seconds, the triangle below the time axis represents a displacement of −½ × 2 × 4 = −4 metres. From 2 to 5 seconds, the triangle above it represents +½ × 3 × 6 = +9 metres. The net displacement is −4 + 9 = 5 metres, while the total distance is 4 + 9 = 13 metres.

Integrating over the whole interval confirms the displacement: [t² − 4t] from 0 to 5 equals 5. To find distance by integration, split at t = 2 and add the magnitudes of the two parts. Annotating those signed areas together online shows why an otherwise correct integration can answer the wrong question.

A-level maths support should reach beyond getting through the current homework. Compare a tutor’s stated course experience with the kind of help you need, then use the introductory conversation to discuss how they would approach it.

Agree a lesson pattern around the learner’s gaps, school workload, time to assessment and budget. A regular weekly session is one possible starting point for ongoing support; a specific difficulty may suit a shorter block. Choose a review point so the pattern can change when the learner’s needs change.