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AQA GCSE Physics 8463 uses Q = I × t: charge Q in coulombs, current I in amperes and time t in seconds. Here is a constructed practice question.

A steady current transfers 180 coulombs of charge in two minutes. What is the current?

A learner rearranges correctly to I = Q ÷ t, then writes 180 ÷ 2 = 90 A. The algebraic step is sound; the time unit is the problem. Convert first: 2 × 60 = 120 seconds. Then I = 180 ÷ 120 = 1.5 A.

The explanation matters as much as the number: 1.5 amperes means 1.5 coulombs pass a point each second. Over 120 seconds, that accounts for all 180 coulombs. A tutor can use this distinction to focus on unit conversion instead of reteaching algebra the learner already understands.

For a follow-up, keep the two-minute interval but transfer 240 coulombs. The current is 240 ÷ 120 = 2 A. Ask the learner to explain why increasing charge in the same time increases current. That checks the physical meaning as well as the calculation.

In AQA A-level Mathematics 7357 mechanics, differentiation and integration connect motion quantities. Consider this constructed example: an object moves along a straight line with velocity v(t) = 2t + 1 m/s, where t is time in seconds, from t = 0 to t = 3.

Differentiation finds how quickly velocity changes, giving acceleration: a = 2 m/s². Integration adds up movement over the interval, giving displacement: [t² + t] from 0 to 3 = 9 + 3 = 12 metres. Velocity stays positive, so the distance travelled is also 12 metres.

Using the final velocity, 7 m/s, for all three seconds would give 21 metres. That overestimates the movement because the object was slower earlier. The graph supplies a second check: its area is a trapezium, (1 + 7) ÷ 2 × 3 = 12 metres.

This is an A-level Maths example. AQA A-level Physics 7408 requires the ideas underlying calculus without requiring explicit differentiation or integration.

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